Pochodna funkcji sin(3x)+arccos(x^2)

$f\left(x\right) =$ $\arccos\left({x}^{2}\right)+\sin\left(3x\right)$

Note: Your input has been rewritten/simplified.

$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$

$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\arccos\left({x}^{2}\right)+\sin\left(3x\right)\right)}}$

$=\class{steps-node}{\cssId{steps-node-2}{\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\arccos\left({x}^{2}\right)\right)}}+\class{steps-node}{\cssId{steps-node-4}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\sin\left(3x\right)\right)}}}}$

$=\class{steps-node}{\cssId{steps-node-7}{\cos\left(3x\right)}}{\cdot}\class{steps-node}{\cssId{steps-node-8}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(3x\right)}}+\class{steps-node}{\cssId{steps-node-5}{\dfrac{-1}{\sqrt{1-{\left({x}^{2}\right)}^{2}}}}}{\cdot}\class{steps-node}{\cssId{steps-node-6}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left({x}^{2}\right)}}$

$=\class{steps-node}{\cssId{steps-node-9}{3}}{\cdot}\cos\left(3x\right)-\dfrac{\class{steps-node}{\cssId{steps-node-10}{2}}\class{steps-node}{\cssId{steps-node-11}{x}}}{\sqrt{1-{x}^{4}}}$

Podziel się rozwiązaniem:

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